Boston Celtics' Enes Kanter fouls Milwaukee Bucks' Giannis Antetokounmpo during the first half of a game Jan. 16, 2020, in Milwaukee. (AP Photo/Morry Gash)

The Milwaukee Bucks are staying home for Christmas, which is becoming an annual perk for reigning NBA champions.

The NBA released the schedule for the Dec. 25 quintupleheader on Tuesday, and the Bucks will play host to the Boston Celtics in the second of the day’s games. It marks the eighth consecutive season in which the reigning champion has gotten to play at home for the holiday.

Also set for Christmas this year: Atlanta opens the day at New York, Golden State visits reigning Western Conference champion Phoenix, Brooklyn plays at the Los Angeles Lakers, and Dallas goes to Utah in the day’s finale.

The full season schedule will be released Friday afternoon, the NBA said. The league is returning to an 82-game season after playing a 72-game slate last season because of the pandemic, and it is expected that the Toronto Raptors — who spent last season playing home games in Tampa, Florida — will be allowed to play in their home city again this season.

Atlanta’s Christmas game will be its first since 1989, ending what was the longest drought in the NBA among franchises with at least one Christmas appearance. Charlotte and Memphis have yet to play on the holiday.

For Lakers star LeBron James, though, Christmas appearances are just about an annual occurrence. And this year’s matchup will likely be of the history-making variety.

If James plays in the Dec. 25 game against the Nets, it would be his 16th Christmas appearance and tie Kobe Bryant for the most in NBA history.

The Bucks, Lakers, Celtics, Nets, Warriors and Mavericks all played on Christmas last season. Utah and New York return for the first time since 2018, and Phoenix is getting its first Christmas game since 2009.